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Find how many terms of the following series are needed to make the given sum: 64+62+60...=0
The sum of a series is calculated with the following formula: n/2(2a+(n-1)d) where n is the number of terms, a is the first term and d is the difference between the terms.
so for this series: n/2(2*64+(n-1)*-2)=0 n(130-2n)=0 n=0 (not valid because n<1) n=65 so the 65th term gives the sum 0
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