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the area of a square is given by the expression x^2-12x+36 square inches. find an expression that represents the length of one side of the square in inches




Sagot :

the area of a square is A=L² where, L is the length of the square and A is the area of the square.

So, 
[tex]L= \sqrt{A} [/tex]..........we get this by square rooting on both sides in the formula

[tex]L= \sqrt{ x^{2} -12x+36} [/tex]

[tex]L= \sqrt{ (x)^{2} -2*x*6+ (6)^{2} } [/tex]..............(a-b)²=a²-2ab+b²

[tex]L= \sqrt{ (x-6)^{2} } [/tex]..................................(a-b)²=a²-2ab+b²

[tex]L=x-6[/tex]...............................square cancels square root

So, the expression that represents the length of one side of square is x - 6 inches.

The area of a square is the products of its dimensions.

The length of one side of the square is x - 6

The area is given as:

[tex]\mathbf{Area = x^2 -12x + 36}[/tex]

Expand

[tex]\mathbf{Area = x^2 -6x - 6x + 36}[/tex]

Factorize

[tex]\mathbf{Area = x(x -6) - 6(x - 6)}[/tex]

Factor out x - 6

[tex]\mathbf{Area = (x -6) (x - 6)}[/tex]

Express as squares

[tex]\mathbf{Area = (x -6)^2}[/tex]

The length of a square is the square root of its area.

So, we have:

[tex]\mathbf{Length= \sqrt{(x -6)^2}}[/tex]

[tex]\mathbf{Length= x -6}[/tex]

Hence, the length of one side of the square is x - 6

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