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What values of x make the two expression below equal?
(2x+1)(x-7)/11(x-7)=2x+1/11

A.) All real numbers expect -1/2
B.) All real numbers
C.) All real numbers expect -1/2 and 7
D.) All real numbers expect 7

Sagot :

Naǫidn
The denominator can't equal 0.
[tex]11(x-7) \not= 0 \\ x-7 \not=0 \\ x \not= 7 \\ \\ \\ \frac{(2x+1)(x-7)}{11(x-7)}=\frac{2x+1}{11} \\ \\ (2x+1)(x-7) \cdot 11= 11(x-7) \cdot (2x+1) \\ 11(2x+1)(x-7)=11(2x+1)(x-7) \\ \\ x \in R \setminus \{7 \}[/tex]

The answer is D.
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