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If an object of 0.550 kg is lifted from the floor to a height of 3.50m, how much work is done by the lifting force, what is the kinetic energy, and what is the velocity?

Sagot :

Luanaidn
[tex]Work=\frac{Force}{distance}\\\\Force=mass*gravity\\Force=0,550*9,8=5,39N\\ distance=3,5m\\\\ Work=\frac{5,39N}{3,5m}=1,54J\\\\ Kinetic\ energy=Work=1,54J\\\\ Kinetic \ energy=\frac{1}{2}mv^2\ \ \ |*2\\ 2Kinetic \ energy=mv^2\\\ \sqrt{\frac{2Kinetic \ energy}{m}}=v\\\\ velocity=\sqrt{\frac{2*1,54}{0,55}}=\sqrt{\frac{3,08}{0,55}}=\sqrt{5,6}=2,37\frac{m}{s} [/tex]
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