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If a radioisotope has a half life of 10 years, how much of the original material would remain after 40 years?

Sagot :

1/8 would remain...
(1/2 is 10 years
1/4 is 20 years
1/8 is 40 years)

Hope this helps! :)
Instead of dividing  the material by half each time, start by dividing 40 years by the half life of ten. This gives you 4. Subtract 1 So you the answer is 1/2 to the 3rd power