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What is the slope of (6,-12), (15,-3)

Sagot :

[tex]Use:m=\frac{y_2-y_1}{x_2-x_1}\\\\====================================\\(6;-12);\ (15;-3)\\\\m=\frac{-3-(-12)}{15-6}=\frac{-3+12}{15-6}=\frac{9}{9}=1\\\\Answer:\boxed{The\ slope\ m=1}[/tex]
Slope (m) is rise/run. Rise on Y-axis and run on X-axis. Therefore...

m = (y2 - y1) / (x2 - x1)

You have two points: 1: (6, -12) and 2: (15, -3)
So... x1 = 6 and y1 = -12
And... x2 = 15 and y2 = -3

Plug and chug:

m = (-3 - (-12)) / (15 - 6)
m = (-3 + 12) / (9)
m = (9) / (9)
m = 1

Your slope is 1!