Join the IDNLearn.com community and start finding the answers you need today. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.
Sagot :
[tex]x+3y=5 \ =>\boxed{x=5-3y} \\\\ 2x+y=5 \\\\ 2(5-3y)+y=5 \\\\10-6y+y=5 \\\\ -5y=5-10 \\\\ -5y=-5 \ |:(-5) \\\\ \boxed{y=1} \\\\ x=5-3*1 \\\\ x=5-3 \\\\ \boxed{x=2} [/tex]
[tex]Elimination\ method:\\ \left\{\begin{array}{ccc}2x+y=5\\x+3y=5&|multiply\ both\ sides\ by\ (-2)\end{array}\right\\+\left\{\begin{array}{ccc}2x+y=5\\-2x-6y=-10\end{array}\right\ \ \ |add\ sides\ of\ the\ equations\\------------\\.\ \ \ \ -5y=-5\ \ \ \ \ |divide\ both\ sides\ by\ (-5)\\.\ \ \ \ \ \ \ \boxed{y=1}\\\\substitute\ the\ value\ of\ y\ into\ one\ of\ the\ equations\ (\#2)\\\\x+3\times1=5\\x+3=5\ \ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\boxed{x=2}\\\center\boxed{Answer:x=2\ and\ y=1\to(2;\ 1)}[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.