Answered

Get personalized and accurate responses to your questions with IDNLearn.com. Ask anything and receive prompt, well-informed answers from our community of experienced experts.

The length of a rectangular picture frame is 2 inches longer than twice the width. If the perimeter of the frame is 34 inches, find the dimensions of the frame.

Sagot :

MichaelLiuidn
The length, l, is 2 more than twice the width, w.
l= 2w+2 (2 more than twice w)
In a rectangle, we have two of the same lengths and two of the same widths.
2l+2w=34
Divide by 2 on each side.
l+w=17
We remember that l is 2w+2
Substituting that back in we get,
2w+2+w=17
3w+2=17
3w=15
w=5
We sub w back into l+w=17
l+5=17
l=12
The dimensions are 5 by 12 inches.
Rabinshrestha41idn
Let,
the length of the rectangular picture frame be "x"
the width of the rectangular picture frame be "y"
Then, according to the question, 
x = 2 + 2y ........................................................equation (1)

Perimeter = 34 inches

Now,
We have,
perimeter of the rectangular = 2 ( length + width)
                                    34 = 2 ( x + y)
                                    34 = 2 ( 2 + 2y + y)
                                    34 = 2 (2 + 3y)
                                    34 = 4 + 6y
                               34 - 4 = 6y
                                    30 = 6y
                               30 / 6 = y
                                      5 = y
Now,
taking equation (1)
x = 2 + 2y
substituting the value of "y" , we get,
x = 2 + 2(5)
x = 2 + 10
x = 12

So, the dimensions of the rectangular frame are 12 inches and 5 inches


 


Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.