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the ratio of the number of adults to the number of students at the prom has to be 1:10. Last year there were 477 more students than adults at the prom. If the school is expecting the same attendance this year, how many adults have to attend the prom?

Sagot :

[tex]Ratio:\ \ \frac{1}{10}\\\\x-number\ of\ adults\\477+x-number\ of\ students\\\\If\ ratio\ is\ \frac{1}{10}, for\ 1\ adult\ is\ 10\ students.\ So\ for\ x\ adults\ is\ 10x\\students.\\\\10x=477+x\ \ \ \ \ \ |substract\ x\\10x-x=477\\9x=477\ \ \ \ |:9\\x=53\\\\10x=10\cdot53=530\\\\There\ were\ 53\ adults\ and\ 530\ students.[/tex]