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One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers

Sagot :

Luanaidn
[tex]x-\ first \ number\\ y-\ second\ number\\\\ x-8=2y\\ x+y-9=14\\\\ x=2y+8\\ x+y=23\\\\ 2y+8+y=23\\ 3y+8=23\ \ \ |subtract\ 8\\ 3y=15\ \ \ |divide\ by\ 3\\ y=5\\\\x=18[/tex]Answer here
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