Answered

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how do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O

Sagot :

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[tex]B(OH)_3=H_3BO_3[/tex]

then

[tex]H_2SO_4+H_3BO_3\longrightarrow~B_2(SO_4)_3+H_2O[/tex]

[tex]\boxed{3H_2SO_4+2H_3BO_3\longrightarrow~B_2(SO_4)_3+6H_2O}[/tex]
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