Braniacidn
Answered

IDNLearn.com: Your go-to resource for finding expert answers. Get the information you need from our community of experts, who provide detailed and trustworthy answers.

Change the equation to show what it would look like if you were getting the value of (b):
Show steps please.

[tex]A= \frac{1}{2}h(b+c) [/tex]

Sagot :

Luanaidn
[tex]A=\frac{1}{2}h(b+c)\ \ \ \ \ |multiply\ by\ 2\\\\ 2a=h(b+c)\ \ \ \ |divide\ by\ h\\\\ \frac{2a}{h}=b+c\ \ \ \ \ |subtract\ c\\\\ \frac{2a}{h}-c=b\\\\Solution\ is\ b=\frac{2a}{h}-c[/tex]
Konrad509idn
[tex]A= \frac{1}{2}h(b+c) \\ 2A=h(b+c)\\ 2A=hb+hc\\ hb=2A-hc\\ b=\frac{2A-hc}{h} [/tex]

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.