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The initial speed of a body is 2.98 m/s.What is its speed after 1.6 s if it accelerates uniformly at 2.51 m/s^2? Answer in units of m/s
What is its speed after 1.6 s if it accelerates uniformly at −2.51 m/s^2? Answer in units of m/s
Not sure if you are saying the acceleration is positive or negative? The equation you would use would be v=u+at, where v=final velocity u=initial velocity a=acceleration t=time. Using this if the acceleration is 2.51m/s^2: v=2.98+(2.51*1.6) v=6.996m/s If the acceleration is -2.51 m/s^2: v=2.98+(2.51*1.6) v=-1.036m/s
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