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how do you solve 8(3a+6)=9(2a-4)

Sagot :

[tex]8(3a+6)=9(2a-4)\ \ \ \ | omiting\ the\ bracket\\\\ 24a+48=18a-36\ \ \ \ | subtract\ 18a\\\\ 6a+48=-36\ \ \ \ | subtract\ 48\\\\ 6a=-84\ \ \ \ | divide\ by\ 6\\\\ a=-14[/tex]
Expand the brackets so you get
24a+48=18a-36

then you take the smaller value of a from both sides which in this case is 18a
so then you are left with
6a+48=-36
then to get 6a on its own, you take away 48 from both sides
6a=-84
then you divide both sides by 6 to get the value of a
a=-14