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how do you solve 8(c-9)=6(2c-12)-4c

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Luanaidn
[tex]8(c-9)=6(2c-12)-4c\ \ \ \ | omiting\ the\ brackets\\\\ 8c-72=12c-72-4c\ \ \ \ | addition\ of\ similar\ numbers\\\\ 8c-72=8c-72\\\\ 0=0\\\\There\ are\ infinitely\ many\ solutions.[/tex]
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