Negravasquez32idn
Answered

IDNLearn.com offers a comprehensive solution for all your question and answer needs. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.

A dragster in a race accelerated from stop to 60 m/s by the time it reached the finish line. The dragster moved in a straight line and traveled from the starting line to the finish line at 8.0 m/s2. How long did it take the dragster?

Sagot :

vf = final velocity
vo = initial velocity
a = acceleration
t = time

use the following equation

vf = vo + at

since vo = 0 m/s (stopped), that term drops out and you're left with . . .

vf = at

(60 m/s) = (8.0 m/s²)t

t = (60 m/s)/(8.0 m/s²) = 7.5 seconds

t = 7.5 seconds

Dragster take 7.5 second.

According to first equation of motion,

V = U + at

t = (V -U)/a

V= final velocity

U=initial velocity

a = acceleration

t = time

given that,

U = 0 m/s (object starts from rest)

V = 60 m/s

a= 8 m/s2

t =?

t = (60 m/s – 0 m/s)/8 m/s2

t = 7.5 s

Thus, we can conclude that, dragster take 7.5 second.

Learn more about equations of motion here:

https://brainly.in/question/17883870

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.