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The sum if three consecutive even numbers is 78
What is the smallest of the three numbers ?

Sagot :

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Let the smallest number equal n. Therefore, the other numbers are (n+2) and (n+4).

The sum of the three numbers are:

[tex]n + (n+2) + (n+4)[/tex]

[tex]=3n+6[/tex]

Since the sum equals 78, 

[tex]3n+6=78[/tex]

Divide both sides by 3, 

[tex]n+2=26[/tex]

[tex]n=24[/tex]

Therefore, the smallest number is 24. 


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