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1/3 as many dimes as nickels
3 more quarters than nickels
17 coins in all
Q=___ D=___ N=___


Sagot :

Use the equations:
17 = D + N+ Q
D=N/3
Q=N+3
Then Substitute D and Q
17 = (N/3)+N+N+3
Solve for N; N=6; then substitute N for D=N/3 and Q=N+3
The answer is
Q=9
D=2
N=6