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1/3 as many dimes as nickels
3 more quarters than nickels
17 coins in all
Q=___ D=___ N=___
Use the equations: 17 = D + N+ Q D=N/3 Q=N+3 Then Substitute D and Q 17 = (N/3)+N+N+3 Solve for N; N=6; then substitute N for D=N/3 and Q=N+3 The answer is Q=9 D=2 N=6
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