Answered

IDNLearn.com: Your trusted platform for finding reliable answers. Find accurate and detailed answers to your questions from our experienced and dedicated community members.

what is the stationary point of y=9x+6x^2-4x^3.need help asap

Sagot :

Konrad509idn
[tex]y=9x+6x^2-4x^3\\ y'=9+12x-12x^2\\ 9+12x-12x^2=0\\ -12x^2+12x+9=0\\ 4x^2-4x-3=0\\ 4x^2-4x+1-4=0\\ (2x-1)^2=4\\ 2x-1=2 \vee 2x-1=-2\\ 2x=3 \vee 2x=-1\\ x=\frac{3}{2} \vee x=-\frac{1}{2}[/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.