Answered

IDNLearn.com offers a reliable platform for finding accurate and timely answers. Ask any question and get a detailed, reliable answer from our community of experts.

what are the real zeros for the function
f(x)=x^2-3x-28

Sagot :

Factor the equation: (x-7)(x+4) Solve for X: X-7=0 x+4=0 X=7 x=-4 A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.
Konrad509idn
[tex]x^2-3x-28=0\\ x^2-7x+4x-28=0\\ x(x-7)+4(x-7)=0\\ (x+4)(x-7)=0\\ x=-4 \vee x=7[/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.