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Sagot :
[tex]2 \ C_6H_{14}_{(g)} + 19 \ O_2_{(g)} \rightarrow 12 \ CO_2_{(g)} + 14 \ H_2O_{(g)}[/tex]
Answer: The balanced reaction is:
2 C6H14(g)+ 19 O2(g) → 12 CO2(g)+ 14 H2O(g)
Note: While balancing the chemical reaction, care must be taken that total number atoms (of each type) on both reactant and product side must be same. In present case, there are 12 'C' atoms, 28 'H' atoms and 38 'O' atoms on both reactant and product side. Hence, the reaction is balanced.
2 C6H14(g)+ 19 O2(g) → 12 CO2(g)+ 14 H2O(g)
Note: While balancing the chemical reaction, care must be taken that total number atoms (of each type) on both reactant and product side must be same. In present case, there are 12 'C' atoms, 28 'H' atoms and 38 'O' atoms on both reactant and product side. Hence, the reaction is balanced.
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