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Does anyone one how to solve this problem

Does Anyone One How To Solve This Problem class=

Sagot :

[tex]( \frac{2}{3} - \frac{1}{6} )[/tex]÷[tex]( \frac{2}{5} - \frac{1}{3} )[/tex]
The first thing you must do it to solve the fractions inside the parentheses first
[tex] \frac{2}{3} - \frac{1}{6} = \frac{4}{6} - \frac{1}{6} [/tex] which is [tex] \frac{3}{6} or \frac{2}{3} [/tex]because you must get a common denominator in order to solve. The common denominator is 6. So you must multiply in order to get 6. [tex] \frac{2}{3} *6= \frac{3}{6} [/tex] Then you do the other fraction: [tex] \frac{2}{5} - \frac{1}{3}= \frac{6}{15} - \frac{5}{15} [/tex] which is [tex] \frac{1}{15} [/tex] because 15 is the common denominator and you must multiply the denominator to get 15, thus, you must multiply by the same amount for the numerator. So now it is [tex] \frac{3}{6} [/tex]÷[tex] \frac{1}{15} [/tex] but when dividing, you just need to flip-flop the second fraction and then multiply across. Now it is [tex] \frac{3}{6} * \frac{15}{1} = \frac{45}{6} [/tex] But to simplify, you find a common factor which is 3.
45÷3=15 and 6÷3=2 which is now [tex] \frac{15}{2} [/tex]
You answer is C)[tex] \frac{15}{2} [/tex]