From health tips to tech hacks, find it all on IDNLearn.com. Our experts are ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
[tex]log_ab+log_ac=log_a(b\cdot c)\\\\log_ab-log_ac=log_a(b:c)\\\\log_ab^c=c\cdot log_ab[/tex]
[tex]\boxed{a)\ log2+log3=log(2\cdot3)=log6}\\\\b)\ log2-log3=log(2:3)=log\frac{2}{3}\\\\c)\ 2log2+log3=log2^2+log3=log4+log3=log(4\cdot3)=log12\\\\d)\ 2log2-log3=log2^2-log3=log4-log3=log(4:3)=log\frac{4}{3}[/tex]
[tex]\boxed{a)\ log2+log3=log(2\cdot3)=log6}\\\\b)\ log2-log3=log(2:3)=log\frac{2}{3}\\\\c)\ 2log2+log3=log2^2+log3=log4+log3=log(4\cdot3)=log12\\\\d)\ 2log2-log3=log2^2-log3=log4-log3=log(4:3)=log\frac{4}{3}[/tex]
Note: Log A + Log b = Log(A*B)
a) log 2 + log 3 = log (2*3)
= log6.
Answer =a.
a) log 2 + log 3 = log (2*3)
= log6.
Answer =a.
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.