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Sagot :
If you multiply the second equation by 3, it becomes:
15x - 6y = 42
Then add the two equations together:
3x + 6y = -6
15x - 6y = 42
+
18x = 36
x = 2
substitute x back into the first equation:
3(2)+6y = -6
6 + 6y = -6
6y = -12
y = -2
So x=2,y=-2
15x - 6y = 42
Then add the two equations together:
3x + 6y = -6
15x - 6y = 42
+
18x = 36
x = 2
substitute x back into the first equation:
3(2)+6y = -6
6 + 6y = -6
6y = -12
y = -2
So x=2,y=-2
[tex] \left \{ {{3x+6y=-6} \atop {5x-2y=14\ \ | *3}} \right. \\\\ \left \{ {{3x+6y=-6} \atop {15x-6y=42}} \right.\\\+-----\\Addition\ method\\\\
18x=36\ \ \ | divide\ by\ 18\\\\x=2\\\\2y=5x-14\\\\
y=\frac{5x-14}{2}=\frac{5*2-14}{2} =\frac{10-14}{2}=-2\\\\Solution\\ \left \{ {{y=-2} \atop {x=2}} \right. [/tex]
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