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what is the time interval between the release of the ball and the time it reaches its maximum hieght? the acceleration gravity is 9.81m/s^2 and the maximum height is 4.4.m. neglect air resistance
We are going to use a kinematics equation and the knowledge that the maximum height of a projectile is achieved when the velocity in the y direction equals 0.
d = vt - (1/2)at² d = -(1/2)at² -2d/a = t² t = √((-2 * 4.4)/(-9.81)) t = √0.897 t = 0.95s
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