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Sagot :
[tex]pH=-log|H_{3}O^{+}|\\\\
pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\
pH=4.62[/tex]
Answer:
The pH of the solution is 4.61.
Explanation:
The pH of the solution is defined as negative logarithm of [tex]H_3O^+[/tex] ion concentration.
[tex]pH=-\log[H_3O^+][/tex]
The concentration of [tex]H_3O^+=2.4\times 10^{-5} molar[/tex]
[tex]pH=-\log[2.4\times 10^{-5} M]=4.61[/tex]
The pH of the solution is 4.61.
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