Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Discover detailed answers to your questions with our extensive database of expert knowledge.
Sagot :
One hour is sixty minutes, so if he runs nine miles in one hour and he only runs for twenty minutes than it should be 9/3= 3 miles
First we have to know how much of one hour is 20 min.
To get it, we have to dividie 20min by 60 min (60 min=1hour), so
20:60=[tex] \frac{20}{60}= \frac{2}{6}= \frac{1}{3} [/tex]
We know that
[tex]v= \frac{s}{t} [/tex]
where v is velocity, s is distance and t is time
We can modify formula to get
[tex]v= \frac{s}{t} \\ v*t=s [/tex]
Now we just have to substitute our data ( t=1/3 and v=9 miles/hour)
s=[tex] \frac{1}{3}*9 [/tex]=3 miles - its the result
To get it, we have to dividie 20min by 60 min (60 min=1hour), so
20:60=[tex] \frac{20}{60}= \frac{2}{6}= \frac{1}{3} [/tex]
We know that
[tex]v= \frac{s}{t} [/tex]
where v is velocity, s is distance and t is time
We can modify formula to get
[tex]v= \frac{s}{t} \\ v*t=s [/tex]
Now we just have to substitute our data ( t=1/3 and v=9 miles/hour)
s=[tex] \frac{1}{3}*9 [/tex]=3 miles - its the result
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.