IDNLearn.com provides a comprehensive solution for all your question and answer needs. Join our knowledgeable community and get detailed, reliable answers to all your questions.
Sagot :
Answer:
The resulting velocity of marble B after the collision is 0.96 m/s.
Explanation:
Mass of marble A ,[tex]m_1= 0.08 kg[/tex]
Initial velocity of the marble A,[tex]u_1 = 0.5 m/s[/tex]
Mass of marble B,[tex]m_2 = 0.05 kg[/tex]
Initial velocity of the marble B,[tex]u_2 = 0 m/s[/tex]
final velocity of the marble A,[tex]v_1 = -0.1 m/s[/tex]
final velocity of the marble B,[tex]v_2 = ?[/tex]
Applying law of conservation of mass:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]0.08 kg\times 0.5 m/s+0.05kg\times 0 m/s=0.08 kg\times (-0.1 m/s)+0.05kg \times v_2[/tex]
[tex] v_2=0.96 /s[/tex]
The resulting velocity of marble B after the collision is 0.96 m/s.
Answer:
the other ball will move with speed 0.96 m/s
Explanation:
Here in collision type of questions we can use momentum conservation because there is no force on the system
So here we will have
[tex]m_a v_{1i} + m_b v_{2i} = m_a v_{1f} + m_b v_{2f}[/tex]
so here we have
[tex]0.08(0.5) + 0.05(0) = 0.08(-0.1) + 0.05 v[/tex]
[tex]0.048 = 0.05 v[/tex]
[tex]v = 0.96 m/s[/tex]
So the light ball will move with speed 0.96 m/s
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.
