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C(squared)L(squared) + 100v(squared) = 100c(squared)
I have to solve for L

Sagot :

first subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²
GrandNecroidn

Answer:

L = ±√( (100c² - 100v²) / C² )

Step-by-step explanation:

You're just doing reverse PEMDAS.

So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.

Then remove all coefficient using multiplication/division.

Then take the sqareroot to get rid of the squre on the v.

Remember that taking squareroot gives a ± answer because

(x)² = (-x)²

View image GrandNecro
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