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13(10b+10)+5(b+2) solve

Sagot :

[tex]13(10b+10)+5(b+2) \\=130b+130+5b+10 \\=135b+140[/tex]
[tex] 13(10b+10)+5(b+2)\\=13(10b)+13(10)+5(b)+5(2)\\=130b+130+5b+10\\=(130b+5b)+(130+10)\\=\boxed{135b+140}[/tex]