Answered

Get expert advice and insights on any topic with IDNLearn.com. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.

A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor


Sagot :

XavierArcheridn
the velocity the hopper jumped at was 4.9 miles per hour
Aabdulsamiridn

Answer: 5.047m/s

Explanation:

Initial velocity (U) = ?

Height (s) = 1.3m

Time taken (t) =?

g = acceleration due to gravity = 9.8m/s²

From equation of motion;

S = ut - ½gt².........equation (i) (note the negative sign is because the Hooper is moving against gravity).

Velocity at maximum height = 0

V = u - gt ........ equation (ii)

0 = u - gt

t = u/g

Put t = u/g into equation (i)

S = u(u/g) - ½g(u/g)²

S = u²/g - ½u²/g

S = ½u²/g

2S = u²/g

U² = 2Sg

U² = 2 * 1.3 * 9.8

U² = 25.48

U = 5.047m/s (take square root of U²)

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.