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x+2y=12
-x=-y-6
how do you solve using substitution method


Sagot :

[tex] \left \{ {{x+2y=12\ \ \ \ \ \ } \atop {-x=-y-6\ \ |*(-1)}} \right. \\\\ \left \{ {{x+2y=12} \atop {x=y+6}} \right. \\\\ using\ substitution \ method\\\\ y+6+2y=12\\ 3y+6=12\ \ | subtract\ 6\\ 3y=6\ \ | divide\ by\ 3\\ y=2\\ x=y+6=2+6=8\\\\ \left \{ {{y=2} \atop {x=8}} \right. [/tex]