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Given that cos (x) = 1/3, find sin (90 - x)

Sagot :

Here2helpidn
A/c to trigonometric relations, sin(90 - x) = cos(x),
that means sin(90 - x) = cos(x) = 1/3.

Answer:

[tex]\sin(90^{\circ} - x)=\frac{1}{3}[/tex]

Step-by-step explanation:

Given: [tex]\cos (x)=\frac{1}{3}[/tex]

We have to find the value of [tex]\sin(90^{\circ} - x)[/tex]

Since Given [tex]\cos (x)=\frac{1}{3}[/tex]

Using trigonometric identity,

[tex]\sin(90^{\circ} - \theta)=\cos\theta[/tex]

Thus, for  [tex]\sin(90^{\circ} - x)[/tex] comparing , we have,

[tex]\theta=x[/tex]

We get,

[tex]\sin(90^{\circ} - x)=\cos x=\frac{1}{3}[/tex]

Thus, [tex]\sin(90^{\circ} - x)=\frac{1}{3}[/tex]

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