IDNLearn.com: Where your questions meet expert advice and community support. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.
How do I solve this problem? You drive your car on a cold day (20^oF Outside) the engine overheats to about (220^oF). When you park the car the engine begins to cool down. The Temperature T of the engine t minutes after you park satisfies the equation:
ln (T-20/200) = - 0.11t
(a) solve the equation for T
T=
(b) Use part of (a) to find the temperature of the engine after 20 min ( t = 20). Round the answer to 1 decimal place
[tex]ln(T- \frac{20}{200})=-0.11t \\ e^{ln(T- \frac{20}{200})}=e^{-0.11t} \\ T- \frac{20}{200} =e^{-0.11t} \\ T-0.1=e^{-0.11t} \\ T=e^{-0.11t}+0.1[/tex] Then, now that we have solved for T, we can evaluate and solve for t=20 minutes. [tex]T=e^{-0.11t}+0.1 \\ T=e^{-0.11*20}+0.1 \\ T=e^{-2.2}+0.1 \\ T=0.11+0.1 \\ T=0.21[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.
