IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Ask your questions and receive accurate, in-depth answers from our knowledgeable community members.
An ideal gas in a sealed container has an initial volume of 2.55 L. At constant pressure, it has cooled to 16.00 degrees Celcius where its final volume is 1.75 L. What was the initial temperature?
Use ideal gas law PV=nRT. The pressure, number of moles, and gas constant are unchanged. Rearrange ideal gas law to get n= PV1/RT1= PV2/RT2 now you can cancel out P and R to get V1/T1 = V2/T2 you know V1= 2.55 L, V2= 1.75 L, T2= 16 degC, you can solve for T1( the initial temperature).
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.
