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What is the value of x in this equation? √3√x+1 ̅= √3x-5 ̅

(square root of X+1 under a square root of 3 =square root of 3x-5)

Sagot :

Luanaidn
[tex]\sqrt{3}\sqrt{x+1}=\sqrt{3x-5}\\\\ \sqrt{3(x+1)}=\sqrt{3x-5}\ \ \ \ | ^{2}\\\\ 3(x+1)=3x-5\\\\ 3x+3=3x-5\ \ \ \ | subtract \ 3x\\\\ 3 \neq -5\\\\ There \ are\ no\ solutions.[/tex]
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