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the product of 2 consecutive #s is 4160 what are the numbers?
so the so the product of two consecutive numbers is 4160 or x(x+1)=4160 distribute x^2+x=4160 subtract 4160 from both sides x^2+x-4160=0 find the factor (if you want to know how, just ask in the comments) (x-64)(x+65)=0 so the answer is x could be 64 or -65 so the number that work are 64,65 and -65,-64
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