Find the best answers to your questions with the help of IDNLearn.com's expert contributors. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.

An automobile engine is 15 percent efficient. How many joules of input work are required to produce 15,000 joules of output work to move the car?


Sagot :

15,000J/.15% = 100,000 J

If you want to check,
Multiply 100,000 by .15 and you get 15,000 J

Answer:100,000Joules

Explanation:

Efficiency of machines is the ratio of work done by machine (work output) to the work put in the machine (work input)

Efficiency = Work output/Work input

Given efficiency = 15%

Work output = 15,000Joules

Work Input = ?

Substituting in the formula of efficiency

15% = 15,000/Work Input

15/100 = 15,000/Work Input

15× Work input = 15,000×100

15 × Work input = 1,500,000

Work input = 1,500,000/15

Work input = 100,000Joules