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Sagot :
First you need to work out what mass of 84g of stainless steel is nickel, and because there's 5% you can simply divide by 20, giving 4.2g
For this you can use the equation [tex]Moles= \frac{Mass}{Mr} [/tex]
The mass, as was worked out previously, is 4.2g
The Mr, which is found on the periodic table, is 28
Moles = [tex] \frac{4.2}{28} [/tex] = 0.15mol
1mol = 6.023 x [tex] 10^{23} [/tex] atoms
So, 0.15mol = 0.15 x 6.023 x [tex] 10^{23} [/tex] = 9.0345 x [tex]10^{22} [/tex] atoms
For this you can use the equation [tex]Moles= \frac{Mass}{Mr} [/tex]
The mass, as was worked out previously, is 4.2g
The Mr, which is found on the periodic table, is 28
Moles = [tex] \frac{4.2}{28} [/tex] = 0.15mol
1mol = 6.023 x [tex] 10^{23} [/tex] atoms
So, 0.15mol = 0.15 x 6.023 x [tex] 10^{23} [/tex] = 9.0345 x [tex]10^{22} [/tex] atoms
First you need to work out what mass of 84g of stainless steel is nickel, and because there's 5% you can simply divide by 20, giving 4.2g
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