Get the answers you've been searching for with IDNLearn.com. Get prompt and accurate answers to your questions from our community of knowledgeable experts.

please help me I'm desperate.

Please Help Me Im Desperate class=

Sagot :

[tex]D:4x-1>0 \wedge x+2 >0 \wedge x>0\\ D:4x>1 \wedge x>-2 \wedge x>0\\ D:x>\frac{1}{4} \wedge x>0\\ D:x>\frac{1}{4}\\\\ \log(4x-1)-\log(x+2)=\log x\\ \log\frac{4x-1}{x+2}=\log x\\ \frac{4x-1}{x+2}=x\\ x(x+2)=4x-1\\ x^2+2x=4x-1\\ x^2-2x+1=0\\ (x-1)^2=0\\ \boxed{x=1} [/tex]
[tex]\log (4x - 1) - \log (x + 2) = \log x[/tex]
[tex]\log ( \frac{4x - 1}{x + 2} ) = \log x[/tex]
[tex] \frac{4x - 1}{x + 2} = x[/tex]
[tex]4x - 1 = x(x + 2)[/tex]
[tex]4x - 1 = x^2 + 2x[/tex]
[tex]0 = x^2 - 2x + 1[/tex]
[tex]0 = (x - 1)^2[/tex]
⇒ [tex]x = 1[/tex]