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A quadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. How many real number solutions does the equation have? help me please

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Superkoopasirfidn
The discriminant of a quadratic is given as [tex]b^2 - 4ac[/tex], so we know that [tex]b^2 - 4ac = -16.[/tex]

When using the quadratic formula to calculate values for [tex]x[/tex], we have to take the root of the discriminant. There is no real answer to the root of a negative number and so the equation has no real roots.

Answer:

A given quadratic equation has no real roots.

Step-by-step explanation:

Given a quadratic equation of the form [tex]ax^2+bx+c=0[/tex] has a discriminant value of –16. we have to find number of real solutions the equation have.

As given discriminant is -16

The formula to find the roots of quadratic equation by discriminant rule is

[tex]x=\frac{-b\pm\sqrt D}{2a}[/tex], [tex]\text{where D is discriminant}[/tex]

[tex]x=\frac{-b\pm\sqrt{-16}}{2a}[/tex]

[tex]x=\frac{-b\pm4i}{2a}[/tex]

which shows that neither of the solutions are real numbers.

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