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How do you factor out the coefficient of the variable in 2/9j + 2/3? (those are fractions by the way) Please help me!! :) Thanks!
So we have [tex] \frac{2}{9}j+ \frac{2}{3} [/tex] We can rewrite it as: [tex] \frac{2}{3*3}j+ \frac{2}{3}= \frac{2}{3}( \frac{1}{3}j + 1) [/tex] - its our result Finally we can take 2/3 in front of parenthesis.
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