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em I right on #9 & 10 algebra 2

Em I Right On 9 Amp 10 Algebra 2 class=

Sagot :

FirstSineOfMadnessidn
#9 is correct.
#10 is actually choice 2.
This is because the difference of logs with the same base (log(x)-log(y)) is equal to the log of the two numbers divided by each other, so log(x)-log(y) would equal log(x/y). In your case, log(15)-log(10) => log(15/10) => log(3/2), final answer.
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