em I right on #9 & 10 algebra 2

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19-11-2014
Mathematics

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em I right on #9 & 10 algebra 2

Sagot :

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FirstSineOfMadnessidn FirstSineOfMadnessidn · Answer 1 · 2014-11-19T21:17:15-05:00

FirstSineOfMadnessidn FirstSineOfMadnessidn

19-11-2014

#9 is correct.
#10 is actually choice 2.
This is because the difference of logs with the same base (log(x)-log(y)) is equal to the log of the two numbers divided by each other, so log(x)-log(y) would equal log(x/y). In your case, log(15)-log(10) => log(15/10) => log(3/2), final answer.

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