Join the IDNLearn.com community and get your questions answered by experts. Ask any question and get a thorough, accurate answer from our community of experienced professionals.
Sagot :
The mass of on P atom would be 31 divided by 6.02 * 10^23
The mass of Avogadro's number of P atoms would be 31, since the atomic weight of and element is the mass of exactly one mole of that element, and Avogadro's number is the number of atoms in one mole.
The mass of Avogadro's number of P atoms would be 31, since the atomic weight of and element is the mass of exactly one mole of that element, and Avogadro's number is the number of atoms in one mole.
Answer:
Mass of Avogadro's number of P atoms = 31 g
Mass of 1 P atom = 5.15*10⁻²³ g
Explanation:
The two rules to consider are:
1) Mass of 1 mole of an element is equal to its molar mass in grams
2) 1 mole of any element contains Avogadro's number of atoms
i.e. 1 mole = 6.023*10^23 atoms(or molecules or particles)
For P-31
1 mole of P-31 = 31 grams
i.e. Mass of Avogadro's number of P atoms = 31 g
6.023*10^23 P atoms = 31 g
Therefore, mass of 1 P atom is:
[tex]= \frac{1\ P\ atom *31\ g}{6.023*10^{23}\ atoms}=5.15*10^{-23}\ g[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.
