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Sagot :
Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
so we want to know what the largest number that can go into both 90 and 120 aka the Greatest common factor or GCF
so 90=3*3*2*5
120=2*2*3*2*5
the number in common are 3*2*5
if we multiply that out we get 30
so 30 is the maximum number of students so that they all share equally so
90/30=3 so each student gets 3 packs of cheese crackers
120/30=4 so each student gets 4 cans of juice
so 90=3*3*2*5
120=2*2*3*2*5
the number in common are 3*2*5
if we multiply that out we get 30
so 30 is the maximum number of students so that they all share equally so
90/30=3 so each student gets 3 packs of cheese crackers
120/30=4 so each student gets 4 cans of juice
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