Answered

IDNLearn.com: Where curiosity meets clarity and questions find their answers. Join our Q&A platform to access reliable and detailed answers from experts in various fields.

A force of 20. Newtons to the left exerted on a cart for 10. Seconds. For what period of time must a 50.-newton force to the right act to produce an impulse of equal magnitude on the cart?

Sagot :

AL2006idn
Impulse = (force) x (time)

The first impulse was (20 N) x (10 sec) = 200 meters/sec

The second one is (50 N) x (time) and we want it equal to the first one, so

(50 N) x (time) = 200 meters/sec

Divide each side by 50N :    Time = 200/50 = 4 seconds

By the way, the quantity we're playing with here is the cart's momentum.
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.