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find the equation of the parabola given the focus (1,4) directrix y=1 ans sketch the graph
ok, so for parabola a(x-h)^2 +k abs(a) = 1/(4c) where c is the distance between the focus and directrix.
The distance is 4-1, or 3 (y coord of the focus - y coord of directrix) so a = 1/(4*3) or 1/12 and the vertex (h,k) is the midpoint of the segment between the focus and directrix, which is (1, 2.5)
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