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Sagot :
Given:
m(g) of Sulfur = 16g
Molar mass of sulfur: 32 g/mol ( from periodic table - atomic mass; mass number or 'A' - the greater number)
Molar Mass of Oxygen: 16 g/mol ( from periodic table from periodic table - atomic mass; mass number or 'A' - the greater number)
Formula used:
n(mol)= m (g) / M (g/mol)
Step One: Write the equation
S + O2 --> SO2
Step Two: Balance the equation ( this one doesn't need balancing)
S + O2 --> SO2
Step Three: Write the molar ratios ( coefficients)
S + O2 --> SO2
1 1 1 <---------molar ratio
Step Four: Find the number of moles of Sulfur (mol) using the formula:
n(mol)= m(g) / M (g/mol)
Substitute 16g in the mass(m) & 32 g/mol in the Molar Mass( g/mol)
n(mol)= 16 (g) / 32 (g/mol)
n(mol) = 0.5 mol of Sulfur
Step Five: Using the molar ratios and the number of moles of Sulfur obtained, cross multiply to find the number of moles of Sulfur dioxide.
( for future reference we don't use O2 because it is in excess, anything in excess we don't use)
S + O2 --> SO2
1 1 1 <---------molar ratio
0.5 x <---------number of moles
1 / 0.5 = 1/x
n ( Sulfur) = n ( sulfur dioxide) since the molar ratio is one to one
n( sulfur dioxide) = 0.5 moles
Step Six: With the given 0.5 moles for Sulfur dioxide calculated, you can find the mass of sulfur dioxide (SO2). You just have to calculate the Molar Mass of Sulfur and Oxygen by using your periodic table. Formula used:
n(mol) = m(g) / M(g/mol)
Molar Mass Calculations
M(O) = 16 g/mol
M(S) = 32 g/mol
M(SO2)= 32 + 16(2) = 32 + 32 = 64 g/mol.
Number of moles of Sulfur dioxide calculated: 0.5 mol
Plug in the values in their corresponding locations:
n(mol) = m(g) / M(g/mol)
0.5(mol) = m(g) / 64 ( g/mol)
m(g) = 0.5 x 64
m(g) = 32 g.
FINAL ANSWER: MASS OF SULFUR DIOXIDE = 32 g.
i hope this was of help:) good luck!
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