IDNLearn.com: Your reliable source for finding expert answers. Our community provides timely and precise responses to help you understand and solve any issue you face.
Sagot :
6x+3x-(x-10)=20x
Distribute -1 to (x-10)
6x+3x-x-(-10)=20x
9x-x-(-10)=20x
8x-(-10)=20x
Subtract 8x to 20x
-10=12x
Divide 12x to -10
-1.2=x
Distribute -1 to (x-10)
6x+3x-x-(-10)=20x
9x-x-(-10)=20x
8x-(-10)=20x
Subtract 8x to 20x
-10=12x
Divide 12x to -10
-1.2=x
in equations we always want to do the same thing to both sides so the equation stays equal
in an equation with one unknown (x) we try to get the unknown on one side
so -(x-10)
this means that you multiply everything in the equation by -1 or in other words you make everything in the parenthasees the opposite sign of what it is so
6x+3x-x+10=20x
add like terms
8x+10=20x
subtract 8x from boths sides
10=12x
divide both sides by 12
10/12=x=5/6
in an equation with one unknown (x) we try to get the unknown on one side
so -(x-10)
this means that you multiply everything in the equation by -1 or in other words you make everything in the parenthasees the opposite sign of what it is so
6x+3x-x+10=20x
add like terms
8x+10=20x
subtract 8x from boths sides
10=12x
divide both sides by 12
10/12=x=5/6
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.