Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.

If 13.0g of CO2 gas has a volume of 0.46L at 310K , what is its pressure in millimeters of mercury?

Sagot :

pV = nRT ---> p = nRT/V
n = m/M, so:  p = mRT/VM, where:
p - pressure
m - mass of CO2 in grams
R - universal gas constant
T - temperature in K
V - volume in L
M - molar mass of CO2 = 44 g/mol

133.3224 Pa = 1 mm Hg

so i think You can handle this right now.